Hello, I use Navigationstack in the first and second views. In this case, the second view is executed immediately and then disappears. Is there a solution? The code is as follows. XCode = 15.0 device = i-phone ContentView.txt SecondScreen.txt thirdScreen.txt

Hello, I use Navigationstack in the first and second views. In this case, the second view is executed immediately and then disappears. Is there a solution? The code is as follows. device = i-phone struct ContentView: View { @State var path: [String] = [] var body: some View { NavigationStack(path: $path) { VStack { Text("Screen1") Spacer() Button(action: { path.append("2nd") }, label: { Text("go to 2nd Screen") }) } .navigationDestination(for: String.self) { s in if s == "2nd" { let _ = print("1st screen nav path(1) = \(path)") SecondScreen(path: $path) let _ = print("1st screen nav path(2) = \(path)") } } .onAppear { print("1st screen on appear") print("1st screen path = \(path)") } .onDisappear { print("1st screen on disappear") print("1st screen disa. path = \(path)") } .padding() } } } struct SecondScreen: View { @State var path2: [String] = [] @Binding var path: [String] var body: some View { NavigationStack(path: $path2) { VStack { Text("2nd Screen is loaded") Spacer() Button(action: { path2.append("3rd") } , label: { Text("go to 3rd Screen") }) Button(action: { path2.removeLast() } , label: { Text("back to 1st Screen") }) } .navigationDestination(for: String.self) { s in if s == "3rd" { // Text("3rd") thirdScreen() } else { thirdScreen() } } } .onAppear { print("2nd screen on appear") print("2nd screen path = \(path)") print("2nd screen path2 = \(path2)") } .onDisappear { print("2nd screen on disappear") print("2nd screen path = \(path)") print("2nd screen disa. path2 = \(path2)") } } } struct thirdScreen: View { var body: some View { VStack { Text("3rd Screen") } .onAppear { print("3rd screen on appear") } .onDisappear { print("3rd screen on disappear") } } }