Hello! I’m trying to handle custom URLs (e.g., customurl://open?param=value) that open the app. However, while the app launches via the custom URL as expected, the parameters are not being passed to or are accessible from the iOS-specific implementation. Currently, if I open a custom URL via Safari, the app gets launched but the custom URL and parameters are not accessible. customurl://open?hello=test According to the iOS Docs ( https://developer.apple.com/documentation/xcode/defining-a-custom-url-scheme-for-your-app#Handle-incoming-URLs ) any URLs should be passed to: func application(_ application: UIApplication, open url: URL, options: [UIApplication.OpenURLOptionsKey : Any] = [:] ) -> Bool I do not register the above application function to be called but instead this one is executed during app start with launchOptions always being nil: func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplication.LaunchOptionsKey : Any]? = nil) -> Bool This is the case regardless of if the App is started fresh or was already running in the background. My pInfo entry for the custom URL: <key>CFBundleURLTypes</key> <array> <dict> <key>CFBundleTypeRole</key> <string>Viewer</string> <key>CFBundleURLName</key> <string>dev.customurl.project</string> <key>CFBundleURLSchemes</key> <array> <string>customurl</string> </array> </dict> <dict/> </array> TLDR: How can I access the parameters, passed with the URL? Any thoughts on what I am doing wrong?