beginner in the code, I block on the line "let fighter = Fighter () ' Xcode displays "Missing argument for parameter 'name' in call"

Question

Created Mar ’21

Replies 6

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Participants 3

I'm beginner in the coding and I block on the line "let fighter = Fighter () '
Xcode displays "Missing argument for parameter 'name' in call"

class Player{

  var name: String
  var characters: [Character] = []

  init(name: String){
    self.name = name
  }

func chooseYourCharacter() {
      if let readline = readLine() {
        if let choose = Int(readline) {
          switch choose {

          case 1:
          let fighter = Fighter()

            fighter.namedCharacter()
            if fighter.goodCharacterName(arrayOfCharacter: self.characters) == true {
              characters.append(fighter)
            }

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Answer 1

OOPer OP

Mar ’21

Accepted Answer

It depends on the definition of Fighter. Please show the code of Fighter.

And please use Code block (see the icon <>) feature of this site when posting codes.
And you should better not show partial code, when parentheses are not matching, there may be some issue in the hidden parts.

1

Answer 2

deborah_sn OP

Mar ’21

Code Block SWIFTclass Fighter : Character{
  init(name: String) {
    super.init(charactersName: name, weapon: Sword(), lifePoint: 100)
  }
}

OK, thanks for your advice, here is my class fighter

0

Answer 3

OOPer OP

Mar ’21

Your Fighter has only one initializer taking a parameter name.
What do you want to pass to the parameter name?

Code Block           let fighter = Fighter(name: ???) //<- You need to clarify what is placed to `???`

0

Answer 4

Claude31 OP

Mar ’21

You could also define an init:

Code Block class Player {
    
    var name: String = "No Name"
    var characters: [Character] = []
    
    init(name: String){
        self.name = name
    }
    
    init() {
    }
}

Then

Code Block let player = Player()
print("Player's name", player.name)

gives
Player's name No Name

Or define name in init()

Code Block class Player {
    
    var name: String
    var characters: [Character] = []
    
    init(name: String) {
        self.name = name
    }
    
    init() {
        self.name = "No Name"
    }
}

same result.

0

Answer 5

deborah_sn OP

Mar ’21

ok, thanks for your help !

0

Answer 6

Claude31 OP

Mar ’21

Don't forget to close the thread when done.

Good continuation.

0