Cannot find type ToolOutput in scope

Question

limtc OP

Created Aug ’25

Replies 3

Boosts 0

Participants 3

My sample app has been working with the following code:


   func call(arguments: Arguments) async throws -> ToolOutput {
        var temp:Int
        
        switch arguments.city {
            case .singapore: temp = Int.random(in: 30..<40)
            case .china: temp = Int.random(in: 10..<30)
        }
        
        let content = GeneratedContent(temp)
        let output = ToolOutput(content)
        return output
    }

However in 26 beta 5, ToolOutput no longer available, please advice what has changed.

Answered by MB-Researcher in 852397022

That's correct! We deprecated ToolOutput in beta 5, and replaced it with either String or GeneratedContent tool output.

For more, see the Tool's doc: https://developer.apple.com/documentation/foundationmodels/tool

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Answer 1

limtc OP

Aug ’25

Accepted Answer

I found that I can change to:

func call(arguments: Arguments) async throws -> GeneratedContent {
        var temp:Int
        
        switch arguments.city {
            case .singapore: temp = Int.random(in: 30..<40)
            case .china: temp = Int.random(in: 10..<30)
        }
        
        return GeneratedContent(temp)
    }

But not sure if this is correct.

2

Answer 2

MB-Researcher OP

4w

Recommended

That's correct! We deprecated ToolOutput in beta 5, and replaced it with either String or GeneratedContent tool output.

For more, see the Tool's doc: https://developer.apple.com/documentation/foundationmodels/tool

1

Answer 3

ahahn94 OP

3w

Will the Landmarks example project from WWDC 25 be updated? It makes use of ToolOutput and thus doesn't work anymore ootb.

1