How to initialize OpenIntent parameter when returning OpensIntent in perform

Question

Created 6d

Replies 2

Boosts 0

Participants 2

I have an app that lets you create cars. I have a CarEntity, an OpenCarIntent, and a CreateCarIntent. I want to support the Open When Run option when creating a car. I understand to do this, you just update the return type of your perform function to include & OpensIntent, then change your return value to include opensIntent: OpenCarIntent(target: carEntity). When I do this, I get a compile-time error:

Cannot convert value of type 'CarEntity' to expected argument type 'IntentParameter<CarEntity>'

What am I doing wrong here?

struct CreateCarIntent: ForegroundContinuableIntent {
    static let title: LocalizedStringResource = "Create Car"
    
    @Parameter(title: "Name")
    var name: String
    
    @MainActor
    func perform() async throws -> some IntentResult & ReturnsValue<CarEntity> & OpensIntent {
        let managedObjectContext = PersistenceController.shared.container.viewContext
        
        let car = Car(context: managedObjectContext)
        car.name = name
        
        try await managedObjectContext.perform {
            try managedObjectContext.save()
        }
        
        let carEntity = CarEntity(car: car)
        return .result(
            value: carEntity,
            opensIntent: OpenCarIntent(target: carEntity) // FIXME: Won't compile
        )
    }
}

struct OpenCarIntent: OpenIntent {
    static let title: LocalizedStringResource = "Open Car"
    
    @Parameter(title: "Car")
    var target: CarEntity
    
    @MainActor
    func perform() async throws -> some IntentResult {
        await UIApplication.shared.open(URL(string: "carapp://cars/view?id=\(target.id)")!)
        return .result()
    }
}

Boost

Answer 1

Jordan OP

5d

Accepted Answer

I figured it out. I needed to add a custom initializer, since I don't have a CarEntity @Parameter to be able to send into the default initializer, I need a plain CarEntity (which can be assigned to the same target variable anyways so that's silly).

init() {}
    
init(carEntity: CarEntity) {
    target = carEntity
}

0

Answer 2

lAppliEnRose OP

3d

Hello

Think different

As for SwiftUI, AppIntents are a kind of pseudocode, you don't see all the real code. Try:

let carEntity = CarEntity(car: car)

// Build, then parameter the intent
let openCarIntent = OpenCarIntent()
openCarIntent.target = openCarIntent

return .result(
            value: carEntity,
            opensIntent: openCarIntent
        )

1