The loop will finish when arrayOfItems is finished. But it is a dynamic array in the sense that sometimes n could be 100 or 1000. I think I could approach the problem like this but it is not efficient and is difficult to read:
In this example, assume arrayOfItems is an array of String items not Integers, so in the loop I will use .indices to obtain the index.
swift
import Foundation
let arrayOfItems = (0...100)
let arrayOfFive = ["Item1", "Item2", "Item3", "Item4", "Item5"]
for index in arrayOfItems {
if (0...4).contains(index) {
print(index)
print(arrayOfFive[index])
} else if (5...9).contains(index) {
print(index)
print(arrayOfFive[index - 5])
} else if (10...19).contains(index) {
if (10...14).contains(index) {
print(index)
print(arrayOfFive[index - 10])
} else {
print(index)
print(arrayOfFive[index - 15])
}
}
}
// Using this approach I will have to create if statements every tens. So, it's not generic for any n numbers
